Percobaan Kisi Difraksi

Menghitung panjang gelombang (lambda) cahaya tampak

lambda = dp/l
d = jarak rata-rata garis warna dari sumber cahaya (m)
p = presisi kisi difraksi (n = 600 garis/mm)
l = jarak antara sumber cahaya dengan kisi difraksi (1m)

solusi :
Kisi difraksi n = 600 garis/mm
p = 1/n
= 1/ (600 garis/mm)
= 1mm/600 garis
= (1/6).10^-5 m/garis

Violet (ungu)
4 x 10^-7 s.d. 4,5 x 10^-7
d = l.lambda/p
= (1 . 4 x 10^-7)/(1/6).10^-5 m/garis
= 4 x 6 . 10^2
= 24 x 10^2 m
= 24 cm
s.d.
= (1 . 4,5 x 10^-7)/(1/6).10^-5 m/garis
= 4,5 x 6 . 10^2
= 27 x 10^2 m
= 27 cm

Biru
4,5 x 10^-7 s.d. 5 x 10^-7
d = l.lambda/p
= (1 . 4,5 x 10^-7)/(1/6).10^-5 m/garis
= 4,5 x 6 . 10^2
= 27 x 10^2 m
= 27 cm
s.d.
= (1 . 5 x 10^-7)/(1/6).10^-5 m/garis
= 5 x 6 . 10^2
= 30 x 10^2 m
= 30 cm

Hijau
5 x 10^-7 s.d. 5,5 x 10^-7
d = l.lambda/p
= (1 . 5 x 10^-7)/(1/6).10^-5 m/garis
= 5 x 6 . 10^2
= 30 x 10^2 m
= 30 cm
s.d.
= (1 . 5,5 x 10^-7)/(1/6).10^-5 m/garis
= 5,5 x 6 . 10^2
= 33 x 10^2 m
= 33 cm

Kuning
5,5 x 10^-7 s.d. 6 x 10^-7
d = l.lambda/p
= (1 . 5,5 x 10^-7)/(1/6).10^-5 m/garis
= 5,5 x 6 . 10^2
= 33 x 10^2 m
= 33 cm
s.d.
= (1 . 6 x 10^-7)/(1/6).10^-5 m/garis
= 6 x 6 . 10^2
= 36 x 10^2 m
= 36 cm

Oranye
6 x 10^-7 s.d. 6.5 x 10^-7
d = l.lambda/p
= (1 . 6 x 10^-7)/(1/6).10^-5 m/garis
= 6 x 6 . 10^2
= 36 x 10^2 m
= 36 cm
s.d.
= (1 . 6,5 x 10^-7)/(1/6).10^-5 m/garis
= 6,5 x 6 . 10^2
= 39 x 10^2 m
= 39 cm

Merah
6,5 x 10^-7 – 7.10^-7 x 10^-7
d = l.lambda/p
= (1 . 6,5 x 10^-7)/(1/6).10^-5 m/garis
= 6,5 x 6 . 10^2
= 39 x 10^2 m
= 39 cm
s.d.
= (1 . 7 x 10^-7):(1/6).10^-5 m/garis
= 7 x 6 . 10^2
= 42 x 10^2 m
= 42 cm

Posted in: fisika